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← JEE Main 2022 · 29 Jul · Shift 2
MathematicsInteger+4 / -1Question 29 of 90

JEE Main 2022 · 29 Jul · Shift 2, Mathematics question 29

Let a⃗\vec a and b⃗\vec b be two vectors such that ∣a⃗+b⃗∣2=∣a⃗∣2+2∣b⃗∣2|\vec a+\vec b|^2=|\vec a|^2+2|\vec b|^2, a⃗⋅b⃗=3\vec a\cdot\vec b=3 and ∣a⃗×b⃗∣2=75|\vec a\times\vec b|^2=75. Then ∣a⃗∣2|\vec a|^2 is equal to _______.

Answer and worked solution

Official answer: 14

Expand. 2a⃗⋅b⃗+∣b⃗∣2=2∣b⃗∣22\vec a\cdot\vec b+|\vec b|^2=2|\vec b|^2 gives ∣b⃗∣2=6|\vec b|^2=6.

Lagrange ∣a⃗∣2∣b⃗∣2−9=75|\vec a|^2|\vec b|^2-9=75, so ∣a⃗∣2=14|\vec a|^2=14.

Answer: 14