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← JEE Main 2022 · 29 Jul · Shift 2
ChemistrySingle correct+4 / -1Question 64 of 90

JEE Main 2022 · 29 Jul · Shift 2, Chemistry question 64

200 mL of 0.01 M HCl is mixed with 400 mL of 0.01 M H2_2SO4_4. The pH of the mixture is _______.

Given: log 2 = 0.30, log 3 = 0.48, log 5 = 0.70, log 7 = 0.84, log 11 = 1.04

Choose one option
Answer and worked solution

Official answer: B

H⁺ 200×0.01+400×0.02600=160\dfrac{200\times0.01+400\times0.02}{600}=\dfrac1{60} M, so pH =log⁡60=1.78=\log60=1.78.

(B)