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← JEE Main 2022 · 29 Jul · Shift 1
MathematicsInteger+4 / -1Question 21 of 90

JEE Main 2022 · 29 Jul · Shift 1, Mathematics question 21

Let S = {θ ∈ (0, 2π) : 7cos⁡2θ−3sin⁡2θ−2cos⁡22θ=27\cos^2\theta-3\sin^2\theta-2\cos^22\theta=2}. Then, the sum of roots of all the equations x2−2(tan⁡2θ+cot⁡2θ)x+6sin⁡2θ=0x^2-2(\tan^2\theta+\cot^2\theta)x+6\sin^2\theta=0, θ ∈ S, is _______.

Answer and worked solution

Official answer: 16

Solve for θ. With c=cos⁡2θc=\cos^2\theta: 8c2−18c+7=08c^2-18c+7=0, so c=12c=\frac12: θ=π4,3π4,5π4,7π4\theta=\frac\pi4,\frac{3\pi}4,\frac{5\pi}4,\frac{7\pi}4.

Each equation is x2−4x+3=0x^2-4x+3=0 with root sum 4. Total 16.

Answer: 16