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← JEE Main 2022 · 28 Jul · Shift 2
ChemistryInteger+4 / -1Question 57 of 90

JEE Main 2022 · 28 Jul · Shift 2, Chemistry question 57

On reaction with stronger oxidizing agent like KIO4\mathrm{KIO_4}, hydrogen peroxide oxidizes with the evolution of O2\mathrm{O_2}. The oxidation number of I in KIO4\mathrm{KIO_4} changes to ______.

Answer and worked solution

Official answer: 5

KIO4→KIO3\mathrm{KIO_4\rightarrow KIO_3}: iodine goes from +7 to +5.

Answer: 5