JEE Main 2022 · 28 Jul · Shift 2 · Chemistry Q56

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ChemistryInteger+4 / -1Question 56 of 90

A sample of 0.125g of an organic compound when analyzed by Duma's method yields 22.78 mL of nitrogen gas collected over KOH solution at 280 K and 759 mm Hg. The percentage of nitrogen in the given organic compound is ______. (Nearest integer)

Given :

(a) The vapour pressure of water of 280 K is 14.2 mm Hg.

(b) R = 0.082 L atm K $^{-1}$ mol $^{-1}$

Your answer

Answer and worked solution

Official answer: 22

Dry nitrogen. $p=\frac{759-14.2}{760}$ atm, so $n=\frac{0.98\times0.02278}{0.082\times280}=9.72\times10^{-4}$ mol (0.0272 g).

Percentage $\frac{0.0272}{0.125}\times100\approx22$ .

Answer: 22

Topics:Qualitative and quantitative analysis of organic compounds

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JEE Main 2022 · 28 Jul · Shift 2, Chemistry question 56