JEE Main 2022 · 28 Jul · Shift 1 · Physics Q40

← JEE Main 2022 · 28 Jul · Shift 1

PhysicsSingle correct+4 / -1Question 40 of 90

Two capacitors, each having capacitance 40 μF are connected in series. The space between one of the capacitors is filled with dielectric material of dielectric constant K such that the equivalence capacitance of the system became 24 μF. The value of K will be :

1.5

2.5

1.2

Answer and worked solution

Official answer: A

Series. $\frac1{24}=\frac1{40}+\frac1{40K}$ , so $\frac1{40K}=\frac1{60}$ and $K=1.5$ .

(A)

Topics:Dielectrics Series and parallel combinations

← Previous question Next question →

JEE Main 2022 · 28 Jul · Shift 1, Physics question 40