In the wave equation
y=0.5sin2πλ(400t−x) my=0.5\sin\frac{2\pi}\lambda(400t-x)\text{ m}y=0.5sinλ2π(400t−x) m
the velocity of the wave will be :
Official answer: C
Form f(t−x/v)f(t-x/v)f(t−x/v) with v=400v=400v=400 m/s.
(C)