JEE Main 2022 · 28 Jul · Shift 1 · Physics Q37

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PhysicsSingle correct+4 / -1Question 37 of 90

A Carnot engine has efficiency of 50%. If the temperature of sink is reduced by 40°C, its efficiency increases by 30%. The temperature of the source will be :

166.7 K

255.1 K

266.7 K

367.7 K

Answer and worked solution

Official answer: C

Initially $T_2=\frac{T_1}2$ .

After. The efficiency rises by 30% of itself to 0.65: $1-\frac{T_1/2-40}{T_1}=0.65$ , so $\frac{40}{T_1}=0.15$ and $T_1=266.7$ K.

(C)

Topics:Carnot cycle

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JEE Main 2022 · 28 Jul · Shift 1, Physics question 37