JEE Main 2022 · 28 Jul · Shift 1 · Physics Q36

PhysicsSingle correct+4 / -1Question 36 of 90

The force required to stretch a wire of cross-section 1 cm $^2$ to double its length will be :

(Given Yong's modulus of the wire = $2\times10^{11}$ N/m $^2$ )

1\times10^7

1.5\times10^7

2\times10^7

2.5\times10^7

Answer and worked solution

Official answer: C

Strain 1. $F=YA\times1=2\times10^{11}\times10^{-4}=2\times10^7$ N.

(C)

Topics:Hooke's law and elastic moduli

JEE Main 2022 · 28 Jul · Shift 1, Physics question 36