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← JEE Main 2022 · 27 Jul · Shift 1
PhysicsInteger+4 / -1Question 59 of 90

JEE Main 2022 · 27 Jul · Shift 1, Physics question 59

A pulley of radius 1.5 m is rotated about its axis by a force F=(12t−3t2)F=\left(12t-3t^2\right) N applied tangentially (while t is measured in seconds). If moment of inertia of the pulley about its axis of rotation is 4.5 kg m2^2, the number of rotations made by the pulley before its direction of motion is reversed, will be Kπ\dfrac K\pi. The value of K is ______.

Answer and worked solution

Official answer: 18

Angular acceleration α=1.5(12t−3t2)4.5=4t−t2\alpha=\frac{1.5(12t-3t^2)}{4.5}=4t-t^2, so ω=2t2−t33\omega=2t^2-\frac{t^3}3, zero again at t=6t=6 s.

Angle θ=∫06ω dt=144−108=36\theta=\int_0^6\omega\,dt=144-108=36 rad, i.e. 18π\frac{18}\pi rotations.

Answer: 18