JEE Main 2022 · 27 Jul · Shift 1 · Physics Q58

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PhysicsInteger+4 / -1Question 58 of 90

A square aluminum (shear modulus is $25\times10^9$ Nm $^{-2}$ ) slab of side 60 cm and thickness 15 cm is subjected to a shearing force (on its narrow face) of $18.0\times10^4$ N. The lower edge is riveted to the floor. The displacement of the upper edge is ______ μm.

Your answer

Answer and worked solution

Official answer: 48

Face area $0.60\times0.15=0.09$ m².

Shear strain $\frac F{AG}=\frac{18\times10^4}{0.09\times25\times10^9}=8\times10^{-5}$ ; times the height 0.60 m gives $4.8\times10^{-5}$ m.

Answer: 48

Topics:Hooke's law and elastic moduli

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JEE Main 2022 · 27 Jul · Shift 1, Physics question 58