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← JEE Main 2022 · 27 Jul · Shift 1
PhysicsInteger+4 / -1Question 53 of 90

JEE Main 2022 · 27 Jul · Shift 1, Physics question 53

Two beams of light having intensities I and 4I interfere to produce a fringe pattern on a screen. The phase difference between the two beams are π/2\pi/2 and π/3\pi/3 at points A and B respectively. The difference between the resultant intensities at the two points is xIxI. The value of xx will be ______.

Answer and worked solution

Official answer: 2

IR=I1+I2+2I1I2cos⁡ϕI_R=I_1+I_2+2\sqrt{I_1I_2}\cos\phi. At A: 5I5I; at B: 5I+4I×12=7I5I+4I\times\frac12=7I.

Difference 2I2I.

Answer: 2