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← JEE Main 2022 · 27 Jul · Shift 1
MathematicsInteger+4 / -1Question 27 of 90

JEE Main 2022 · 27 Jul · Shift 1, Mathematics question 27

Let f(x)=2x2−x−1f(x)=2x^2-x-1 and S={n∈Z:∣f(n)∣≤800}S=\{n\in\mathbf Z:|f(n)|\le800\}. Then, the value of ∑n∈Sf(n)\displaystyle\sum_{n\in S}f(n) is equal to ______.

Answer and worked solution

Official answer: 10620

Range. 2n2−n−1≤8002n^2-n-1\le800 for −19≤n≤20-19\le n\le20, and f≥−800f\ge-800 always.

Sum. ∑n2=2⋅2470+400=5340\sum n^2=2\cdot2470+400=5340, ∑n=20\sum n=20, 40 terms: 10680−20−40=1062010680-20-40=10620.

Answer: 10620