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← JEE Main 2022 · 27 Jul · Shift 1
MathematicsInteger+4 / -1Question 26 of 90

JEE Main 2022 · 27 Jul · Shift 1, Mathematics question 26

Let M and N be the number of points on the curve y5−9xy+2x=0y^5-9xy+2x=0, where the tangents to the curve are parallel to xx-axis and yy-axis, respectively. Then the value of M+NM+N equals ______.

Answer and worked solution

Official answer: 2

Slope. dydx=9y−25y4−9x\frac{dy}{dx}=\frac{9y-2}{5y^4-9x}.

Horizontal tangents need y=29y=\frac29, but then the curve gives (29)5=0\left(\frac29\right)^5=0. Impossible, so M=0M=0.

Vertical tangents need 5y4=9x5y^4=9x. With x=y59y−2x=\frac{y^5}{9y-2} this gives 36y5=10y436y^5=10y^4: y=0y=0 or y=518y=\frac5{18}, so N=2N=2.

Answer: 2