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← JEE Main 2022 · 26 Jul · Shift 2
PhysicsInteger+4 / -1Question 59 of 90

JEE Main 2022 · 26 Jul · Shift 2, Physics question 59

A potentiometer wire of length 300 cm is connected in series with a resistance 780 Ω and a standard cell of emf 4 V. A constant current flows through potentiometer wire. The length of the null point for cell of emf 20 mV is found to be 60 cm. The resistance of the potentiometer wire is ______ Ω.

Answer and worked solution

Official answer: 20

Gradient. 20 mV over 60 cm means 100 mV across the 300 cm wire.

Divider. RR+780×4=0.1\frac R{R+780}\times4=0.1, so 40R=R+78040R=R+780 and R=20R=20 Ω.

Answer: 20