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← JEE Main 2022 · 26 Jul · Shift 2
PhysicsInteger+4 / -1Question 58 of 90

JEE Main 2022 · 26 Jul · Shift 2, Physics question 58

In a coil of resistance 8 Ω, the magnetic flux due to an external magnetic field varies with time as ϕ=23(9−t2)\phi=\dfrac23\left(9-t^2\right). The value of total heat produced in the coil, till the flux becomes zero, will be ______ J.

Answer and worked solution

Official answer: 2

emf ∣dϕdt∣=43t\left|\frac{d\phi}{dt}\right|=\frac43t; the flux is zero at t=3t=3 s.

Heat ∫0316t2/98dt=29×9=2\int_0^3\frac{16t^2/9}{8}dt=\frac29\times9=2 J.

Answer: 2