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← JEE Main 2022 · 26 Jul · Shift 2
MathematicsInteger+4 / -1Question 25 of 90

JEE Main 2022 · 26 Jul · Shift 2, Mathematics question 25

If the sum of solutions of the system of equations 2sin⁡2θ−cos⁡2θ=02\sin^2\theta-\cos2\theta=0 and 2cos⁡2θ+3sin⁡θ=02\cos^2\theta+3\sin\theta=0 in the interval [0,2π][0,2\pi] is kπk\pi, then kk is equal to ______.

Answer and worked solution

Official answer: 3

First equation. 2sin⁡2θ−(1−2sin⁡2θ)=02\sin^2\theta-(1-2\sin^2\theta)=0: sin⁡2θ=14\sin^2\theta=\frac14.

Second. 2−2sin⁡2θ+3sin⁡θ=02-2\sin^2\theta+3\sin\theta=0: sin⁡θ=−12\sin\theta=-\frac12 (2 is impossible).

Common solutions 7π6,11π6\frac{7\pi}6,\frac{11\pi}6, sum 3π3\pi.

Answer: 3