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← JEE Main 2022 · 26 Jul · Shift 1
PhysicsInteger+4 / -1Question 59 of 90

JEE Main 2022 · 26 Jul · Shift 1, Physics question 59

In the hydrogen spectrum, λ\lambda be the wavelength of first transition line of Lyman series. The wavelength difference will be "aλa\lambda" between the wavelength of 3rd^{\text{rd}} transition line of Paschen series and that of 2nd^{\text{nd}} transition line of Balmer series where a=a= ______.

Answer and worked solution

Official answer: 5

Wavelengths in units of the Lyman first line λ=43R\lambda=\frac4{3R}: Paschen third line (6→36\to3) is 9λ9\lambda, Balmer second line (4→24\to2) is 4λ4\lambda.

Difference 5λ5\lambda.

Answer: 5