JEE Main 2022 · 26 Jul · Shift 1 · Physics Q58

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PhysicsInteger+4 / -1Question 58 of 90

The graph between $\dfrac1u$ and $\dfrac1v$ for a thin convex lens in order to determine its focal length is plotted as shown in the figure. The refractive index of lens is 1.5 and its both the surfaces have same radius of curvature R. The value of R will be ______ cm.

(where $u$ = object distance, $v$ = image distance)

1/v (cm⁻¹) against 1/u (cm⁻¹): a straight line from B (−0.10, 0) to A (0, 0.10).

Your answer

Answer and worked solution

Official answer: 10

Intercepts give $\frac1f=0.10$ cm $^{-1}$ , $f=10$ cm. Lens maker $\frac1f=0.5\cdot\frac2R$ : $R=10$ cm.

Answer: 10

Topics:Thin lenses and lens maker's formula Focal length measurements

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JEE Main 2022 · 26 Jul · Shift 1, Physics question 58