JEE Main 2022 · 25 Jul · Shift 2 · Physics Q37

← JEE Main 2022 · 25 Jul · Shift 2

PhysicsSingle correct+4 / -1Question 37 of 90

The ratio of wavelengths of proton and deuteron accelerated by potential $V_p$ and $V_d$ is $1:\sqrt2$ . Then, the ratio of $V_p$ to $V_d$ will be :

1:1

\sqrt2

2 : 1

4 : 1

Answer and worked solution

Official answer: D

$\lambda=\dfrac h{\sqrt{2mqV}}$ , same charge, $m_d=2m_p$ : $\dfrac{\lambda_p}{\lambda_d}=\sqrt{\dfrac{2V_d}{V_p}}=\dfrac1{\sqrt2}$ , so $V_p:V_d=4:1$ .

(D)

Topics:de Broglie waves

← Previous question Next question →

JEE Main 2022 · 25 Jul · Shift 2, Physics question 37