JEE Main 2022 · 25 Jul · Shift 2 · Physics Q35

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PhysicsSingle correct+4 / -1Question 35 of 90

For a free body diagram shown in the figure, the four forces are applied in the ' $x$ ' and ' $y$ ' directions. What additional force must be applied and at what angle with positive x-axis so that the net acceleration of body is zero ?

A body at the origin with forces 7 N along +y, 8 N along −y, 5 N along +x and 6 N along −x.

\sqrt2

N, 45°

\sqrt2

N, 135°

\dfrac2{\sqrt3}

N, 30°

2N, 45°

Answer and worked solution

Official answer: A

Net force $(5-6,7-8)=(-1,-1)$ N; the balancing force is $(1,1)$ : $\sqrt2$ N at $45°$ .

(A)

Topics:Newton's laws Vectors

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JEE Main 2022 · 25 Jul · Shift 2, Physics question 35