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← JEE Main 2022 · 25 Jul · Shift 2
MathematicsSingle correct+4 / -1Question 13 of 90

JEE Main 2022 · 25 Jul · Shift 2, Mathematics question 13

The tangents at the points A(1,3)A(1,3) and B(1,−1)B(1,-1) on the parabola y2−2x−2y=1y^2-2x-2y=1 meet at the point P. Then the area (in unit2^2) of the triangle PAB is:

Choose one option
Answer and worked solution

Official answer: D

Tangents. At AA: 2y−x=52y-x=5; at BB: 2y+x=−12y+x=-1. They meet at P(−3,1)P(-3,1).

Area. AB=4AB=4 on x=1x=1, height 4: area 8.

(D)