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← JEE Main 2022 · 25 Jul · Shift 2
MathematicsSingle correct+4 / -1Question 12 of 90

JEE Main 2022 · 25 Jul · Shift 2, Mathematics question 12

If the ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 meets the line x7+y26=1\dfrac x7+\dfrac y{2\sqrt6}=1 on the xx-axis and the line x7−y26=1\dfrac x7-\dfrac y{2\sqrt6}=1 on the yy-axis, then the eccentricity of the ellipse is

Choose one option
Answer and worked solution

Official answer: A

Intercepts. (7,0)(7,0) and (0,−26)(0,-2\sqrt6): a=7a=7, b2=24b^2=24.

Eccentricity 1−2449=57\sqrt{1-\frac{24}{49}}=\frac57.

(A)

Topics:Ellipse