JEE Main 2022 · 25 Jul · Shift 2 · Chemistry Q64

← JEE Main 2022 · 25 Jul · Shift 2

ChemistrySingle correct+4 / -1Question 64 of 90

The molar conductivity of a conductivity cell filled with 10 moles of 20 mL NaCl solution is $\Lambda_{m1}$ and that of 20 moles another identical cell heaving 80 mL NaCl solution is $\Lambda_{m2}$ . The conductivities exhibited by these two cells are same. The relationship between $\Lambda_{m2}$ and $\Lambda_{m1}$ is

\Lambda_{m2}=2\Lambda_{m1}

\Lambda_{m2}=\Lambda_{m1}/2

\Lambda_{m2}=\Lambda_{m1}

\Lambda_{m2}=4\Lambda_{m1}

Answer and worked solution

Official answer: A

$\Lambda_m=\frac\kappa c$ with equal κ: $c_1=\frac{10}{0.02}$ , $c_2=\frac{20}{0.08}$ , half as much, so $\Lambda_{m2}=2\Lambda_{m1}$ .

(A)

Topics:Conductance and Kohlrausch's law

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JEE Main 2022 · 25 Jul · Shift 2, Chemistry question 64