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← JEE Main 2022 · 25 Jul · Shift 2
ChemistrySingle correct+4 / -1Question 63 of 90

JEE Main 2022 · 25 Jul · Shift 2, Chemistry question 63

Ka1K_{a_1}, Ka2K_{a_2} and Ka3K_{a_3} are the respective ionization constants for the following reactions (a), (b), and (c).

(a) H2C2O4⇌H++HC2O4−\mathrm{H_2C_2O_4\rightleftharpoons H^++HC_2O_4^-}

(b) HC2O4−⇌H++C2O42−\mathrm{HC_2O_4^-\rightleftharpoons H^++C_2O_4^{2-}}

(c) H2C2O4⇌2H++C2O42−\mathrm{H_2C_2O_4\rightleftharpoons2H^++C_2O_4^{2-}}

The relationship between Ka1K_{a_1}, Ka2K_{a_2} and Ka3K_{a_3} is given as

Choose one option
Answer and worked solution

Official answer: D

Adding reactions (a) and (b) gives (c), so Ka3=Ka1Ka2K_{a_3}=K_{a_1}K_{a_2}.

(D)