JEE Main 2022 · 25 Jul · Shift 1 · Physics Q60

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PhysicsInteger+4 / -1Question 60 of 90

The required height of a TV tower which can cover the population of 6.03 lakh is h. If the average population density is 100 per square km and the radius of earth is 6400 km, then the value of h will be ______ m.

Your answer

Answer and worked solution

Official answer: 150

Area $\frac{6.03\times10^5}{100}=6030$ km² $=2\pi Rh$ , so $h=\frac{6030}{2\pi\times6400}\approx0.15$ km $=150$ m.

Answer: 150

Topics:Propagation of EM waves

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JEE Main 2022 · 25 Jul · Shift 1, Physics question 60