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← JEE Main 2022 · 25 Jul · Shift 1
ChemistrySingle correct+4 / -1Question 61 of 90

JEE Main 2022 · 25 Jul · Shift 1, Chemistry question 61

SO2Cl2\mathrm{SO_2Cl_2} on reaction with excess of water results into acidic mixture

SO2Cl2+2H2O→H2SO4+2HCl\mathrm{SO_2Cl_2+2H_2O\rightarrow H_2SO_4+2HCl}

16 moles of NaOH is required for the complete neutralisation of the resultant acidic mixture. The number of moles of SO2Cl2\mathrm{SO_2Cl_2} used is :

Choose one option
Answer and worked solution

Official answer: C

Acid. Each SO2Cl2\mathrm{SO_2Cl_2} gives H2SO4+2HCl\mathrm{H_2SO_4}+2\mathrm{HCl}, which take 4 NaOH: 164=4\frac{16}4=4 mol.

(C)