JEE Main 2022 · 30 Jun · Shift 1 · Physics Q47

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PhysicsSingle correct+4 / -1Question 47 of 90

Find the ratio of maximum intensity to the minimum intensity in the interference pattern if the widths of the two slits in Young's experiment are in the ratio of 9 : 16.

(Assuming intensity of light is directly proportional to the width of slits)

3 : 4

4 : 3

7 : 1

49 : 1

Answer and worked solution

Official answer: D

Amplitudes $3:4$ : $\dfrac{I_{max}}{I_{min}}=\left(\dfrac{4+3}{4-3}\right)^2=49$ .

(D)

Topics:Interference and Young's double slit

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JEE Main 2022 · 30 Jun · Shift 1, Physics question 47