JEE Main 2022 · 30 Jun · Shift 1 · Physics Q46

← JEE Main 2022 · 30 Jun · Shift 1

PhysicsSingle correct+4 / -1Question 46 of 90

In series RLC resonator, if the self inductance and capacitance become double, the new resonant frequency ( $f_2$ ) and new quality factor ( $Q_2$ ) will be :

( $f_1$ = original resonant frequency, $Q_1$ = original quality factor)

f_2=\dfrac{f_1}2

and

Q_2=Q_1

f_2=f_1

and

Q_2=\dfrac{Q_1}2

f_2=2f_1

and

Q_2=Q_1

f_2=f_1

and

Q_2=2Q_1

Answer and worked solution

Official answer: A

$f\propto\frac1{\sqrt{LC}}$ halves; $Q=\frac1R\sqrt{\frac LC}$ is unchanged.

(A)

Topics:LCR circuits and resonance

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JEE Main 2022 · 30 Jun · Shift 1, Physics question 46