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JEE Main 2022 · 30 Jun · Shift 1, Physics question 31

At t=0t=0, truck, starting from rest, moves in the positive xx-direction at uniform acceleration of 5 ms−2^{-2}. At t=20t=20 s, a ball is released from the top of the truck. The ball strikes the ground in 1 s after the release. The velocity of the ball, when it strikes the ground, will be :

(Given g=10g=10 ms−2^{-2})

Choose one option
Answer and worked solution

Official answer: A

At release the ball moves with the truck: 5×20=1005\times20=100 m s−1^{-1} along x, which stays constant. After 1 s of fall it also has −10-10 m s−1^{-1} along y.

(A)

Topics:Motion in a planeRelative velocity
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