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← JEE Main 2022 · 30 Jun · Shift 1
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JEE Main 2022 · 30 Jun · Shift 1, Mathematics question 30

Let S1={x∈[0,12π]:sin⁡5x+cos⁡5x=1}S_1=\left\{x\in[0,12\pi]:\sin^5x+\cos^5x=1\right\} and S2={x∈[0,8π]:sin⁡7x+cos⁡7x=1}S_2=\left\{x\in[0,8\pi]:\sin^7x+\cos^7x=1\right\}. Then n(S1)−n(S2)n(S_1)-n(S_2) is equal to ______.

Answer and worked solution

Official answer: 4

Equality sin⁡nx+cos⁡nx=1\sin^nx+\cos^nx=1 (n=5,7n=5,7) only when one of them is 1 and the other 0: x=2kπx=2k\pi or π2+2kπ\frac\pi2+2k\pi.

Counts. [0,12π][0,12\pi]: 7+6=137+6=13. [0,8π][0,8\pi]: 5+4=95+4=9. Difference 4.

Answer: 4