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JEE Main 2022 · 30 Jun · Shift 1, Chemistry question 85

100 mL of 0.3 M acetic acid is shaken with 0.8 g of wood charcoal. The final concentration of acetic acid in the solution after adsorption is 0.125 M. The mass of acetic acid adsorbed per gram of carbon is ______ ×10−4\times10^{-4} g.

(Given : Molar mass of acetic acid = 60 g mol−1^{-1})

Answer and worked solution

Official answer: 13125

Adsorbed. 0.1×(0.3−0.125)=0.01750.1\times(0.3-0.125)=0.0175 mol =1.05=1.05 g on 0.8 g: 1.3125 g per gram =13125×10−4=13125\times10^{-4} g.

Answer: 13125

Topics:Adsorption
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