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← JEE Main 2022 · 29 Jun · Shift 2
ChemistryInteger+4 / -1Question 85 of 90

JEE Main 2022 · 29 Jun · Shift 2, Chemistry question 85

The equation k=(6.5×1012s−1)e−26000K/Tk=\left(6.5\times10^{12}\text{s}^{-1}\right)e^{-26000\text{K}/T} is followed for the decomposition of compound A. The activation energy for the reaction is ______ kJ mol−1^{-1}. [nearest integer]

(Given: R = 8.314 J K−1^{-1}mol−1^{-1})

Answer and worked solution

Official answer: 216

Arrhenius. EaR=26000\frac{E_a}R=26000 K: Ea=26000×8.314≈216E_a=26000\times8.314\approx216 kJ mol−1^{-1}.

Answer: 216