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← JEE Main 2022 · 29 Jun · Shift 2
ChemistryInteger+4 / -1Question 84 of 90

JEE Main 2022 · 29 Jun · Shift 2, Chemistry question 84

The cell potential for the given cell at 298 K

Pt ∣ H2(g,1 bar) ∣ H+(aq) ∣∣ Cu2+(aq) ∣ Cu(s)\mathrm{Pt\,|\,H_2(g,1\,bar)\,|\,H^+(aq)\,||\,Cu^{2+}(aq)\,|\,Cu(s)}

is 0.31V. The pH of the acidic solution is found to be 3, whereas the concentration of Cu2+\mathrm{Cu^{2+}} is 10−x10^{-x} M. The value of xx is ______.

(Given: ECu2+/Cu⊖=0.34E^\ominus_{\mathrm{Cu^{2+}/Cu}}=0.34 V and 2.303RTF=0.06\dfrac{2.303RT}F=0.06 V)

Answer and worked solution

Official answer: 7

Nernst. 0.31=0.34−0.03log⁡[H+]2[Cu2+]=0.34−0.03(x−6)0.31=0.34-0.03\log\dfrac{[\mathrm{H^+}]^2}{[\mathrm{Cu^{2+}}]}=0.34-0.03(x-6), so x=7x=7.

Answer: 7