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← JEE Main 2022 · 29 Jun · Shift 2
ChemistryInteger+4 / -1Question 82 of 90

JEE Main 2022 · 29 Jun · Shift 2, Chemistry question 82

2.2 g of nitrous oxide (N2O\mathrm{N_2O}) gas is cooled at a constant pressure of 1 atm from 310 K to 270 K causing the compression of the gas from 217.1 mL to 167.75 mL. The change in internal energy of the process, ΔU\Delta U is '−x-x' J. The value of 'xx' is ______. [nearest integer]

(Given: atomic mass of N = 14 g mol−1^{-1} and of O = 16 g mol−1^{-1}. Molar heat capacity of N2O\mathrm{N_2O} is 100 J K−1^{-1}mol−1^{-1})

Answer and worked solution

Official answer: 195

Heat. q=nCpΔT=0.05×100×(−40)=−200q=nC_p\Delta T=0.05\times100\times(-40)=-200 J.

Work on the gas. −PΔV=1×0.04935-P\Delta V=1\times0.04935 L atm ≈+5.0\approx+5.0 J.

ΔU\Delta U =−195=-195 J.

Answer: 195