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← JEE Main 2022 · 29 Jun · Shift 2
ChemistryInteger+4 / -1Question 81 of 90

JEE Main 2022 · 29 Jun · Shift 2, Chemistry question 81

A box contains 0.90 g of liquid water in equilibrium with water vapour at 27°C. The equilibrium vapour pressure of water at 27°C is 32.0 Torr. When the volume of the box is increased, some of the liquid water evaporates to maintain the equilibrium pressure. If all the liquid water evaporates, then the volume of the box must be ______ litre. [nearest integer]

(Given: R = 0.082 L atm K−1^{-1} mol−1^{-1})

(Ignore the volume of the liquid water and assume water vapours behave as an ideal gas.)

Answer and worked solution

Official answer: 29

Moles 0.050.05. V=nRTP=0.05×0.082×30032/760≈29V=\dfrac{nRT}P=\dfrac{0.05\times0.082\times300}{32/760}\approx29 L.

Answer: 29