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JEE Main 2022 · 29 Jun · Shift 1, Physics question 60

For the network shown below, the value of VB−VAV_B-V_A is ______ V.

Single loop: from A, a 15 V cell then a 1 Ω resistor to B along the top; the bottom branch from B back to A has a 2 Ω resistor.
Answer and worked solution

Official answer: 10

Loop current. 151+2=5\frac{15}{1+2}=5 A.

From A to B along the top: rise of 15 V across the cell, drop of 5 V across 1 Ω: VB−VA=10V_B-V_A=10 V.

Answer: 10

Topics:Kirchhoff's laws
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