JEE Main 2022 · 29 Jun · Shift 1 · Chemistry Q61

ChemistrySingle correct+4 / -1Question 61 of 90

Production of iron in blast furnace follows the following equation

$\mathrm{Fe_3O_4(s)+4CO(g)\rightarrow3Fe(l)+4CO_2(g)}$

when 4.640 kg of $\mathrm{Fe_3O_4}$ and 2.520 kg of CO are allowed to react then the amount of iron (in g) produced is :

[Given : Molar Atomic mass (g mol $^{-1}$ ) : Fe = 56; Molar Atomic mass (g mol $^{-1}$ ) : O = 16; Molar Atomic mass (g mol $^{-1}$ ) : C = 12]

1400

2200

3360

4200

Answer and worked solution

Official answer: C

Moles. $\mathrm{Fe_3O_4}$ $\frac{4640}{232}=20$ , CO $\frac{2520}{28}=90$ (needs only 80): $\mathrm{Fe_3O_4}$ limits.

Iron. $60\times56=3360$ g.

(C)

Topics:Stoichiometry

JEE Main 2022 · 29 Jun · Shift 1, Chemistry question 61