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← JEE Main 2022 · 29 Jun · Shift 1
PhysicsInteger+4 / -1Question 58 of 90

JEE Main 2022 · 29 Jun · Shift 1, Physics question 58

A transistor is used in an amplifier circuit in common emitter mode. If the base current changes by 100 μ\muA, it brings a change of 10 mA in collector current. If the load resistance is 2 kΩ\Omega and input resistance is 1 kΩ\Omega, the value of power gain is x×104x\times10^4. The value of xx is ______.

Answer and worked solution

Official answer: 2

Current gain β=10 mA100 μA=100\beta=\frac{10\text{ mA}}{100\ \mu\text{A}}=100.

Power gain. β2RLRin=104×2=2×104\beta^2\frac{R_L}{R_{in}}=10^4\times2=2\times10^4.

Answer: 2