JEE Main 2022 · 29 Jun · Shift 1 · Mathematics Q25

MathematicsInteger+4 / -1Question 25 of 90

The number of solutions of the equation $2\theta-\cos^2\theta+\sqrt2=0$ in $\mathbf R$ is equal to ______.

Your answer

Answer and worked solution

Official answer: 1

Monotonic. $f(\theta)=2\theta-\cos^2\theta+\sqrt2$ has $f'=2+\sin2\theta>0$ and runs from $-\infty$ to $\infty$ : one root.

Answer: 1

JEE Main 2022 · 29 Jun · Shift 1, Mathematics question 25