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← JEE Main 2022 · 29 Jun · Shift 1
MathematicsInteger+4 / -1Question 24 of 90

JEE Main 2022 · 29 Jun · Shift 1, Mathematics question 24

The number of elements in the set S={θ∈[−4π,4π]:3cos⁡22θ+6cos⁡2θ−10cos⁡2θ+5=0}S=\left\{\theta\in[-4\pi,4\pi]:3\cos^22\theta+6\cos2\theta-10\cos^2\theta+5=0\right\} is ______.

Answer and worked solution

Official answer: 32

Simplify with c=cos⁡2θc=\cos2\theta: 3c2+6c−5(1+c)+5=3c2+c=03c^2+6c-5(1+c)+5=3c^2+c=0, so c=0c=0 or −13-\frac13.

Count. 2θ∈[−8π,8π]2\theta\in[-8\pi,8\pi]: each value gives 16 solutions.

Answer: 32