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JEE Main 2022 · 28 Jun · Shift 2, Physics question 60

A car covers AB distance with first one-third at velocity v1v_1 ms−1^{-1}, second one-third at v2v_2 ms−1^{-1} and last one-third at v3v_3 ms−1^{-1}. If v3=3v1v_3=3v_1, v2=2v1v_2=2v_1 and v1=11v_1=11 ms−1^{-1} then the average velocity of the car is ______ ms−1^{-1}.

Line from A to B divided into three equal parts travelled at v1, v2 and v3.
Answer and worked solution

Official answer: 18

Equal distances. vˉ=31v1+12v1+13v1=1811v1=18\bar v=\dfrac3{\frac1{v_1}+\frac1{2v_1}+\frac1{3v_1}}=\dfrac{18}{11}v_1=18 m s−1^{-1}.

Answer: 18

Topics:Motion in a straight line
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