JEE Main 2022 · 28 Jun · Shift 2 · Chemistry Q61

ChemistrySingle correct+4 / -1Question 61 of 90

Compound A contains 8.7% Hydrogen, 74% Carbon and 17.3% Nitrogen. The molecular formula of the compound is,

Given : Atomic masses of C, H and N are 12, 1 and 14 amu respectively.

The molar mass of the compound A is 162 g mol $^{-1}$ .

\mathrm{C_4H_6N_2}

\mathrm{C_2H_3N}

\mathrm{C_5H_7N}

\mathrm{C_{10}H_{14}N_2}

Answer and worked solution

Official answer: D

Moles. C $\frac{74}{12}=6.17$ , H 8.7, N $\frac{17.3}{14}=1.24$ : ratio 5 : 7 : 1, empirical formula $\mathrm{C_5H_7N}$ (81).

Molecular formula. $\frac{162}{81}=2$ : $\mathrm{C_{10}H_{14}N_2}$ .

(D)

Topics:Empirical and molecular formula

JEE Main 2022 · 28 Jun · Shift 2, Chemistry question 61