JEE Main 2022 · 28 Jun · Shift 1 · Physics Q37

← JEE Main 2022 · 28 Jun · Shift 1

PhysicsSingle correct+4 / -1Question 37 of 90

Given below are two statements :

Statement - I : When $\mu$ amount of an ideal gas undergoes adiabatic change from state $(P_1,V_1,T_1)$ to state $(P_2,V_2,T_2)$ , then work done is $W=\dfrac{\mu R(T_2-T_1)}{1-\gamma}$ , where $\gamma=\dfrac{C_P}{C_V}$ and R = universal gas constant.

Statement - II : In the above case, when work is done on the gas, the temperature of the gas would rise.

Choose the correct answer from the options given below:

Both statement-I and statement-II are true.

Both statement-I and statement-II are false.

Statement-I is true but statement-II is false.

Statement-I is false but statement-II is true.

Answer and worked solution

Official answer: A

Statement I. Work done by the gas in an adiabatic change is $\dfrac{\mu R(T_1-T_2)}{\gamma-1}=\dfrac{\mu R(T_2-T_1)}{1-\gamma}$ : true.

Statement II. With $Q=0$ , work done on the gas raises its internal energy, so its temperature rises: true.

(A)

Topics:Thermodynamic processes Work done by a gas

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JEE Main 2022 · 28 Jun · Shift 1, Physics question 37