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← JEE Main 2022 · 27 Jun · Shift 2
ChemistryInteger+4 / -1Question 84 of 90

JEE Main 2022 · 27 Jun · Shift 2, Chemistry question 84

When 5 moles of He gas expand isothermally and reversibly at 300 K from 10 litre to 20 litre, the magnitude of the maximum work obtained is ______ J. [nearest integer] (Given : R=8.3R=8.3 J K−1^{-1}mol−1^{-1} and log⁡2=0.3010\log2=0.3010)

Answer and worked solution

Official answer: 8630

Reversible isothermal work. nRTln⁡V2V1=5×8.3×300×2.303×0.3010≈8630nRT\ln\dfrac{V_2}{V_1}=5\times8.3\times300\times2.303\times0.3010\approx8630 J.

Answer: 8630