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← JEE Main 2022 · 27 Jun · Shift 2
ChemistryInteger+4 / -1Question 83 of 90

JEE Main 2022 · 27 Jun · Shift 2, Chemistry question 83

BeO reacts with HF in presence of ammonia to give [A] which on thermal decomposition produces [B] and ammonium fluoride. Oxidation state of Be in [A] is ______.

Answer and worked solution

Official answer: 2

A. BeO+2NH3+4HF→(NH4)2[BeF4]+H2O\mathrm{BeO+2NH_3+4HF\rightarrow(NH_4)_2[BeF_4]+H_2O}; on heating it gives BeF2\mathrm{BeF_2} (B) and NH4F\mathrm{NH_4F}.

Oxidation state of Be in [BeF4]2−\mathrm{[BeF_4]^{2-}}: +2.

Answer: 2