JEE Main 2022 · 27 Jun · Shift 2 · Chemistry Q80

← JEE Main 2022 · 27 Jun · Shift 2

ChemistryList match+4 / -1Question 80 of 90

Match List I with List II.

Choose the correct answer from the options given below:

List I (Anion)

A
$\mathrm{CO_3^{2-}}$
B
$\mathrm{S^{2-}}$
C
$\mathrm{SO_3^{2-}}$
D
$\mathrm{NO_2^-}$

List II (gas evolved on reaction with dil $\mathrm{H_2SO_4}$)

I
Colourless gas which turns lead acetate paper black.
II
Colourless gas which turns acidified potassium dichromate solution green.
III
Brown fumes which turns acidified KI solution containing starch blue.
IV
Colourless gas evolved with brisk effervescence, which turns lime water milky.

A-III, B-I, C-II, D-IV

A-II, B-I, C-IV, D-III

A-IV, B-I, C-III, D-II

A-IV, B-I, C-II, D-III

Answer and worked solution

Official answer: D

Gases with dilute acid. $\mathrm{CO_3^{2-}}$ : $\mathrm{CO_2}$ , effervescence, milky lime water (IV). $\mathrm{S^{2-}}$ : $\mathrm{H_2S}$ , blackens lead acetate (I). $\mathrm{SO_3^{2-}}$ : $\mathrm{SO_2}$ , turns dichromate green (II). $\mathrm{NO_2^-}$ : brown $\mathrm{NO_2}$ fumes, starch-iodide blue (III).

(D)

Topics:Anion analysis

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JEE Main 2022 · 27 Jun · Shift 2, Chemistry question 80