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JEE Main 2022 · 27 Jun · Shift 1, Physics question 46

An observer moves towards a stationary source of sound with a velocity equal to one-fifth of the velocity of sound. The percentage change in the frequency will be :

Choose one option
Answer and worked solution

Official answer: A

Moving observer. f′=f(1+vov)=1.2ff'=f\left(1+\dfrac{v_o}v\right)=1.2f: a 20% increase.

(A)

Topics:Doppler effect
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