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← JEE Main 2022 · 27 Jun · Shift 1
PhysicsSingle correct+4 / -1Question 45 of 90

JEE Main 2022 · 27 Jun · Shift 1, Physics question 45

The displacement of simple harmonic oscillator after 3 seconds starting from its mean position is equal to half of its amplitude. The time period of harmonic motion is :

Choose one option
Answer and worked solution

Official answer: D

From mean position. sin⁡2π(3)T=12\sin\dfrac{2\pi(3)}T=\dfrac12, so 6πT=π6\dfrac{6\pi}T=\dfrac\pi6 and T=36T=36 s.

(D)