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← JEE Main 2022 · 26 Jun · Shift 2
PhysicsInteger+4 / -1Question 57 of 90

JEE Main 2022 · 26 Jun · Shift 2, Physics question 57

Two 10 cm long, straight wires, each carrying a current of 5 A are kept parallel to each other. If each wire experienced a force of 10−510^{-5} N, then separation between the wires is ______ cm.

Answer and worked solution

Official answer: 5

Force between wires. F=μ0I2l2πdF=\dfrac{\mu_0I^2l}{2\pi d}, so d=2×10−7×25×0.110−5=0.05d=\dfrac{2\times10^{-7}\times25\times0.1}{10^{-5}}=0.05 m =5=5 cm.

Answer: 5